Christmas cracker pulling: How to send everyone home a winner

December 15, 2014, Wiley

According to experts' statistical analyses, if you're expecting 10 guests for dinner on Christmas day, 15 crackers—those festive cardboard tubes filled with a one-size-fits-no-one paper hat, a small toy, and a groan-inducing joke—should be enough to send everyone home happy. The experts came to their estimation by simulating 10,000 parties, with guest numbers ranging from 2 to 50. Their results are published in Significance.

In the traditional approach, all dinner guests sit around the table, cross arms, and pull with their two immediate neighbors. In this approach, each person has a 25% chance of winning zero crackers, so there are clearly inefficiencies in the system.

A better approach would be to use a system that starts by pairing up individuals and having each pair pull a single cracker. (For odd-sized groups one individual will have to stir the gravy or check the goose while this takes place.) Exactly [N/2] crackers are used in this round, with the same number of winners and losers.

Those who have not yet won continue as before until only a single individual remains. That individual then pulls a cracker with themselves and we are done.

Explore further: Back to Nature rice crackers recalled

More information: Clifford, D., Lê Cao, K.-A. and Huang, B. E. (2014), A statistician's Christmas party. Significance, 11: 44-47. DOI: 10.1111/j.1740-9713.2014.00784.x

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